| how to truncate? |
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| fuzz |
| Posted: 10-January-2007 at 7:01pm | IP Logged
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Newbie
Group: Newbie
Joined: 23-September-2006
Location: United States
Posts: 14
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My teachers said there was a code to truncate decimals, but didn't tell us how. By truncating decimals i mean like changing 5.25678 to 5.256. If anyone knows how please reply with the code. It doesn't matter the compiler. Thanks
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| neWWe}{ |
| Posted: 11-January-2007 at 5:55am | IP Logged
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Dedicated Groupie
Group: Dedicated Groupie
Joined: 07-January-2007
Location: France
Posts: 44
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if you mean truncate when using printf then you can use this
printf("%.3f",f); //leaves only 3 decimals
printf("%10.3f",f); //prints f on 10 positions & 3 decimals
printf("%10f",f); //prints f on 10 positions
try to test to understand how it works
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| fuzz |
| Posted: 11-January-2007 at 8:11pm | IP Logged
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Newbie
Group: Newbie
Joined: 23-September-2006
Location: United States
Posts: 14
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what i need is a code that does not round but truncate its, ex. 5.376 truncated to the .01 would be 5.37, if it would be rounded it would display 5.38. What you game me rounds the number, but thanks for the help!
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| neWWe}{ |
| Posted: 12-January-2007 at 1:09pm | IP Logged
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Dedicated Groupie
Group: Dedicated Groupie
Joined: 07-January-2007
Location: France
Posts: 44
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then use this
void truncate(float *n, int d)
{
int t=1;
while(n) t*=10;
return ((float)( (int)(*n*t) ))/(float)t;
}
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| DutchDude |
| Posted: 19-June-2007 at 11:49am | IP Logged
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Super Dedicated Groupie
Group: Super Dedicated Groupie
Joined: 02-April-2007
Location: Netherlands
Posts: 71
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LOL, It's actually that simple Simplicity is my biggest friend, my only friend realy.
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| em1189 |
| Posted: 13-September-2007 at 3:41pm | IP Logged
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Newbie
Group: Newbie
Joined: 13-September-2007
Posts: 2
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#include<iomanip>
cout << setpoint(n) << fixed
replace "n" with the number of decimal places you want, put this line in after your declaration statements and before your assignment statements....
edit: sorry just tested this and it does round the number
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| m4ster_r0shi |
| Posted: 27-March-2010 at 7:30am | IP Logged
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Newbie
Group: Newbie
Joined: 26-March-2010
Posts: 4
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check this out:
-----------------------------------------
-----------------------------------------
#include <iostream>
#include <cmath>
using namespace std;
double truncate(double number,int pos)
{
//this will hold the truncated value
double truncated;
// is our number positive or negative?
int sign;
sign=number>0?1:-1;
//integer and decimal parts of our number
unsigned int int_part;
unsigned int dec_part;
//work with absolute value
number=fabs(number);
//break down our number...
int_part=number;
int pot=pow(10.0,pos); //pot -> power of ten, LOL
dec_part=(number-int_part)*pot;
//...and build the truncated one
truncated=int_part;
truncated+=double(dec_part)/pot;
//fix the sign
truncated*=sign;
return truncated;
}
int main()
{
double d1=123.456;
double d2=-456.321;
int i;
for (i=3; i>=0; i--)
cout << "truncate(" << d1 << "," << i << ")=" << truncate(d1,i) << endl;
for (i=3; i>=0; i--)
cout << "truncate(" << d2 << "," << i << ")=" << truncate(d2,i) << endl;
system("pause");
return 0;
}
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